2019 AMC 10A Problem 23


Travis has to babysit the terrible Thompson triplets. Knowing that they love big numbers, Travis devises a counting game for them. First Tadd will say the number 11, then Todd must say the next two numbers (22 and 33), then Tucker must say the next three numbers (44, 55, 66), then Tadd must say the next four numbers (77, 88, 99, 1010), and the process continues to rotate through the three children in order, each saying one more number than the previous child did, until the number 10,00010,000 is reached. What is the 20192019th number said by Tadd?

(A) 5743(B) 5885(C) 5979(D) 6001(E) 6011\textbf{(A)}\ 5743 \qquad\textbf{(B)}\ 5885 \qquad\textbf{(C)}\ 5979 \qquad\textbf{(D)}\ 6001 \qquad\textbf{(E)}\ 6011

Show/Hide Hints

Show/Hide Problem Tags

Problem Tags: Counting and probability

Want to contribute problems and receive full credit? Click here to add your problem!
Please report any issues to us in our Discord server
Go to previous contest problem (SHIFT + Left Arrow) Go to next contest problem (SHIFT + Right Arrow)
Category: AMC 10A
Points: 4
Back to practice