2008 Gauss 8 Problem 24

The sum of all of the digits of the integers from 98 to 101 is 9 + 8 + 9 + 9 + 1 + 0 + 0 + 1 + 0 + 1 = 38 The sum of all of the digits of the integers from 1\ \text{to} 2008 is

\textbf{(A)}\ 30\,054\quad \textbf{(B)}\ 27\,018\quad \textbf{(C)}\ 28\,036\quad \textbf{(D)}\ 30\,036\quad \textbf{(E)}\ 28\,054

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Gauss contests here.