2014 AIME II Problem 12


Suppose that the angles of ABC\triangle ABC satisfy cos(3A)+cos(3B)+cos(3C)=1\cos(3A) + \cos(3B) + \cos(3C) = 1. Two sides of the triangle have lengths 1010 and 1313. There is a positive integer mm so that the maximum possible length for the remaining side of ABC\triangle ABC is m\sqrt{m}. Find mm.


Leading zeroes must be inputted, so if your answer is 34, then input 034. Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.

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Category: AIME II
Points: 5
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