2004 AMC 10A Problem 18


A sequence of three real numbers form an arithmetic progression with a first term of 99. If 22 is added to the second term and 2020 is added to the third term, the three resulting numbers form a geometric progression. What is the smallest possible value for the third term of the geometric progression?

(A) 1(B) 4(C) 36(D) 49(E) 81\mathrm{(A) \ } 1 \qquad \mathrm{(B) \ } 4 \qquad \mathrm{(C) \ } 36 \qquad \mathrm{(D) \ } 49 \qquad \mathrm{(E) \ } 81

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Category: AMC 10A
Points: 3
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