2003 AIME I Problem 15


In ABC\triangle ABC, AB=360AB = 360, BC=507BC = 507, and CA=780CA = 780. Let MM be the midpoint of CA\overline{CA}, and let DD be the point on CA\overline{CA} such that BD\overline{BD} bisects angle ABCABC. Let FF be the point on BC\overline{BC} such that DFBD\overline{DF} \perp \overline{BD}. Suppose that DF\overline{DF} meets BM\overline{BM} at EE. The ratio DE:EFDE: EF can be written in the form m/nm/n, where mm and nn are relatively prime positive integers. Find m+nm + n.


Leading zeroes must be inputted, so if your answer is 34, then input 034. Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.

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Category: AIME I
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