{"status": "success", "data": {"description_md": "**Full credit goes to the staff team at Canada Math for authoring these problems.**\n\nLet $ABCD$ be a rectangle with $AB > AD = 100$. A circle $\\Omega$ is tangent to sides $AB$ at $X$, $BC$ at $Y$, and $CD$ and $Z$. Let the tangent from $D$ to $\\Omega$ intersect $\\Omega$ at $P \\neq Z$. If $A$, $P$, $Y$ are collinear find $AB$.", "description_html": "

Full credit goes to the staff team at Canada Math for authoring these problems.

Let ABCD be a rectangle with AB > AD = 100. A circle \\Omega is tangent to sides AB at X, BC at Y, and CD and Z. Let the tangent from D to \\Omega intersect \\Omega at P \\neq Z. If A, P, Y are collinear find AB.

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