{"status": "success", "data": {"description_md": "In triangle $ABC$, $A'$, $B'$, and $C'$ are on the sides $BC$, $AC$, and $AB$, respectively. Given that $AA'$, $BB'$, and $CC'$ are concurrent at the point $O$, and that $$\\frac{AO}{OA'}+\\frac{BO}{OB'}+\\frac{CO}{OC'}=92, $$find $$\\frac{AO}{OA'}\\cdot \\frac{BO}{OB'}\\cdot \\frac{CO}{OC'}. $$\n___\nLeading zeroes must be inputted, so if your answer is `34`, then input `034`. Full credit goes to [MAA](https://maa.org/) for authoring these problems. These problems were taken on the [AOPS](https://artofproblemsolving.com/) website.", "description_html": "<p>In triangle <span class=\"katex--inline\">ABC</span>, <span class=\"katex--inline\">A'</span>, <span class=\"katex--inline\">B'</span>, and <span class=\"katex--inline\">C'</span> are on the sides <span class=\"katex--inline\">BC</span>, <span class=\"katex--inline\">AC</span>, and <span class=\"katex--inline\">AB</span>, respectively. Given that <span class=\"katex--inline\">AA'</span>, <span class=\"katex--inline\">BB'</span>, and <span class=\"katex--inline\">CC'</span> are concurrent at the point <span class=\"katex--inline\">O</span>, and that <span class=\"katex--display\">\\frac{AO}{OA'}+\\frac{BO}{OB'}+\\frac{CO}{OC'}=92,</span>find <span class=\"katex--display\">\\frac{AO}{OA'}\\cdot \\frac{BO}{OB'}\\cdot \\frac{CO}{OC'}.</span></p>&#10;<hr><p>Leading zeroes must be inputted, so if your answer is <code>34</code>, then input <code>034</code>. Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 6, "problem_name": "1992 AIME Problem 14", "can_next": true, "can_prev": true, "nxt": "/problem/92_aime_p15", "prev": "/problem/92_aime_p13"}}