{"status": "success", "data": {"description_md": "Raashan, Sylvia, and Ted play the following game. Each person starts with $1$ dollar. A bell rings every $12$ seconds, at which time each of the players who currently have money simultaneously chooses one of the other two players independently and at random and gives $1$ dollar to that player. What is the probability that after the bell has rung $2019$ times, each player will have $1$ dollar?
(For example, Raashan and Ted may each decide to give $1$ dollar to Sylvia, and Sylvia may decide to give her dollar to Ted, at which point Raashan will have $0$ dollar, Sylvia will have $2$ dollars, and Ted will have $1$ dollar, and that is the end of the first round of play. In the second round Rashaan has no money to give, but Sylvia and Ted might choose each other to give their $1$ dollar to, and the holdings will be the same at the end of the second round.)\n\n$\\textbf{(A) } \\frac{1}{7} \\qquad\\textbf{(B) } \\frac{1}{4} \\qquad\\textbf{(C) } \\frac{1}{3} \\qquad\\textbf{(D) } \\frac{1}{2} \\qquad\\textbf{(E) } \\frac{2}{3}$\n___\nFull credit goes to [MAA](https://maa.org/) for authoring these problems. These problems were taken on the [AOPS](https://artofproblemsolving.com/) website.", "description_html": "

Raashan, Sylvia, and Ted play the following game. Each person starts with 1 dollar. A bell rings every 12 seconds, at which time each of the players who currently have money simultaneously chooses one of the other two players independently and at random and gives 1 dollar to that player. What is the probability that after the bell has rung 2019 times, each player will have 1 dollar?
(For example, Raashan and Ted may each decide to give 1 dollar to Sylvia, and Sylvia may decide to give her dollar to Ted, at which point Raashan will have 0 dollar, Sylvia will have 2 dollars, and Ted will have 1 dollar, and that is the end of the first round of play. In the second round Rashaan has no money to give, but Sylvia and Ted might choose each other to give their 1 dollar to, and the holdings will be the same at the end of the second round.)

\\textbf{(A) } \\frac{1}{7} \\qquad\\textbf{(B) } \\frac{1}{4} \\qquad\\textbf{(C) } \\frac{1}{3} \\qquad\\textbf{(D) } \\frac{1}{2} \\qquad\\textbf{(E) } \\frac{2}{3}

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.

", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 3, "problem_name": "2019 AMC 12B Problem 19", "can_next": true, "can_prev": true, "nxt": "/problem/19_amc12B_p20", "prev": "/problem/19_amc12B_p18"}}