{"status": "success", "data": {"description_md": "For some positive integer $n$, the number $110n^3$ has $110$ positive integer divisors, including $1$ and the number $110n^3$. How many positive integer divisors does the number $81n^4$ have?\n\n$\\textbf{(A) }110\\qquad\\textbf{(B) }191\\qquad\\textbf{(C) }261\\qquad\\textbf{(D) }325\\qquad\\textbf{(E) }425$", "description_html": "<p>For some positive integer  <span class=\"katex--inline\">n</span> , the number  <span class=\"katex--inline\">110n^3</span>  has  <span class=\"katex--inline\">110</span>  positive integer divisors, including  <span class=\"katex--inline\">1</span>  and the number  <span class=\"katex--inline\">110n^3</span> . How many positive integer divisors does the number  <span class=\"katex--inline\">81n^4</span>  have?</p>\n<p> <span class=\"katex--inline\">\\textbf{(A) }110\\qquad\\textbf{(B) }191\\qquad\\textbf{(C) }261\\qquad\\textbf{(D) }325\\qquad\\textbf{(E) }425</span> </p>\n<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 4, "problem_name": "2016 AMC 10A Problem 22", "can_next": true, "can_prev": true, "nxt": "/problem/16_amc10A_p23", "prev": "/problem/16_amc10A_p21"}}