{"status": "success", "data": {"description_md": "In the figure shown below, $ABCDE$ is a regular pentagon and $AG=1$. What is $FG+JH+CD$?\n\n<center>\n<img class=\"problem-image\" height=\"235\" src=\"https://latex.artofproblemsolving.com/5/9/2/59250f12e369fe9d6250e65d1fe45f718c64e3a5.png\" width=\"252\"/>\n</center>\n\n$\\textbf{(A) } 3 \\qquad\\textbf{(B) } 12-4\\sqrt5 \\qquad\\textbf{(C) } \\dfrac{5+2\\sqrt5}{3} \\qquad\\textbf{(D) } 1+\\sqrt5 \\qquad\\textbf{(E) } \\dfrac{11+11\\sqrt5}{10}$", "description_html": "<p>In the figure shown below,  <span class=\"katex--inline\">ABCDE</span>  is a regular pentagon and  <span class=\"katex--inline\">AG=1</span> . What is  <span class=\"katex--inline\">FG+JH+CD</span> ?</p>\n<center>\n<img class=\"problem-image\" height=\"235\" src=\"https://latex.artofproblemsolving.com/5/9/2/59250f12e369fe9d6250e65d1fe45f718c64e3a5.png\" width=\"252\"/>\n</center>\n<p> <span class=\"katex--inline\">\\textbf{(A) } 3 \\qquad\\textbf{(B) } 12-4\\sqrt5 \\qquad\\textbf{(C) } \\dfrac{5+2\\sqrt5}{3} \\qquad\\textbf{(D) } 1+\\sqrt5 \\qquad\\textbf{(E) } \\dfrac{11+11\\sqrt5}{10}</span> </p>\n<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 4, "problem_name": "2015 AMC 10B Problem 22", "can_next": true, "can_prev": true, "nxt": "/problem/15_amc10B_p23", "prev": "/problem/15_amc10B_p21"}}